What is the integral of-(16)/(x^{17)} ?

The integral of-(16)/(x^{17)} is 1/(x^{16)}+C

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integral of-(16)/(x^{17)}

\int - \frac{16}{x ^{17}} d x

\frac{1}{x ^{16}} + C

Solution steps

\int - \frac{16}{x ^{17}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 16 \cdot \int \frac{1}{x ^{17}} d x

Apply the Power Rule

: - \frac{1}{16 x ^{16}}

= - 16 (- \frac{1}{16 x ^{16}})

Simplify

- 16 (- \frac{1}{16 x ^{16}}) : \frac{1}{x ^{16}}

= \frac{1}{x ^{16}}

Add a constant to the solution

= \frac{1}{x ^{16}} + C

n = 1 \sum \infty \frac{6 ^{n}}{5 ^{n}}

\frac{d y}{d x} = 2 y - 4 x e^{x}

x^{2} cos (x)

\int \frac{x}{9 x - 8} d x

What is the integral of-(16)/(x^{17)} ?
The integral of-(16)/(x^{17)} is 1/(x^{16)}+C