What is the integral of (1+2x)^4(2) ?

The integral of (1+2x)^4(2) is 1/5 (1+2x)^5+C

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integral of (1+2x)^4(2)

\int (1 + 2 x)^{4} (2) d x

\frac{1}{5} (1 + 2 x)^{5} + C

Solution steps

\int (1 + 2 x)^{4} \cdot 2 d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int (1 + 2 x)^{4} d x

Apply u-substitution

: \int \frac{u ^{4}}{2} d u

= 2 \cdot \int \frac{u ^{4}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int u^{4} d u

Apply the Power Rule

: \frac{u ^{5}}{5}

= 2 \cdot \frac{1}{2} \cdot \frac{u ^{5}}{5}

Substitute back

u = 1 + 2 x

= 2 \cdot \frac{1}{2} \cdot \frac{( 1 + 2 x ) ^{5}}{5}

Simplify

2 \cdot \frac{1}{2} \cdot \frac{( 1 + 2 x ) ^{5}}{5} : \frac{1}{5} (1 + 2 x)^{5}

= \frac{1}{5} (1 + 2 x)^{5}

Add a constant to the solution

= \frac{1}{5} (1 + 2 x)^{5} + C

\frac{5}{x ^{5}}

(x^{2} - y) d x - x d y = 0

\int \frac{e ^{2 x}}{x} d x

y x

\int (1 + x^{2}) (2 - x) d x

What is the integral of (1+2x)^4(2) ?
The integral of (1+2x)^4(2) is 1/5 (1+2x)^5+C