What is the derivative of 4x^3-238x^2+3160x ?

The derivative of 4x^3-238x^2+3160x is 12x^2-476x+3160

What is the first derivative of 4x^3-238x^2+3160x ?

The first derivative of 4x^3-238x^2+3160x is 12x^2-476x+3160

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\frac{d}{d x} (4 x^{3} - 238 x^{2} + 3160 x)

12 x^{2} - 476 x + 3160

Solution steps

\frac{d}{d x} (4 x^{3} - 238 x^{2} + 3160 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (238 x^{2}) + \frac{d}{d x} (3160 x)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (238 x^{2}) = 476 x

\frac{d}{d x} (3160 x) = 3160

= 12 x^{2} - 476 x + 3160

cos^{2} (e^{x} + x)

\int_{0}^{1} 6 x^{2} - 1 d x

\frac{\partial}{\partial y} (- e^{x - y} x)

\int x cos (8 x^{2} + π) d x

What is the derivative of 4x^3-238x^2+3160x ?
The derivative of 4x^3-238x^2+3160x is 12x^2-476x+3160
What is the first derivative of 4x^3-238x^2+3160x ?
The first derivative of 4x^3-238x^2+3160x is 12x^2-476x+3160