What is the solution for (dx)/(dt)+2tx=1 ?

The solution for (dx)/(dt)+2tx=1 is x=(sqrt(pi)\erfi(t))/(2e^{t^2)}+(c_{1})/(e^{t^2)}

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(dx)/(dt)+2tx=1

\frac{d x}{d t} + 2 t x = 1

x = \frac{π erfi ( t )}{2 e ^{t^{2}}} + \frac{c _{1}}{e ^{t^{2}}}

Solution steps

\frac{d x}{d t} + 2 t x = 1

Solve linear ODE:

x = \frac{π erfi ( t )}{2 e ^{t^{2}}} + \frac{c _{1}}{e ^{t^{2}}}

x = \frac{π erfi ( t )}{2 e ^{t^{2}}} + \frac{c _{1}}{e ^{t^{2}}}

tan (4) x^{3}

x \to 0 lim (\frac{x}{x ^{2} + 7 x})

\int e^{x + 5} d x

\frac{d}{d x} (\frac{tan ( \frac{x}{2} ) + cot ( \frac{x}{2} )}{x})

\frac{d}{d x} (\frac{∣ x - 2 ∣}{x ^{2}})

What is the solution for (dx)/(dt)+2tx=1 ?
The solution for (dx)/(dt)+2tx=1 is x=(sqrt(pi)\erfi(t))/(2e^{t^2)}+(c_{1})/(e^{t^2)}