What is the integral of sin(x^2)x ?

The integral of sin(x^2)x is -1/2 cos(x^2)+C

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integral of sin(x^2)x

\int sin (x^{2}) x d x

- \frac{1}{2} cos (x^{2}) + C

Solution steps

\int sin (x^{2}) x d x

Apply u-substitution

: \int \frac{sin ( u )}{2} d u

= \int \frac{sin ( u )}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{2} (- cos (u))

Substitute back

u = x^{2}

= \frac{1}{2} (- cos (x^{2}))

Simplify

= - \frac{1}{2} cos (x^{2})

Add a constant to the solution

= - \frac{1}{2} cos (x^{2}) + C

x \to 2 lim (x - 1)

\frac{d}{d x} (\frac{2 x + 1}{x + 5} (3 x - 1))

t^{2} y^{^{''}} + 19 t y^{^{'}} + 117 y = 0

- 10 x

\frac{d}{d x} (cot (f (x)))

What is the integral of sin(x^2)x ?
The integral of sin(x^2)x is -1/2 cos(x^2)+C