What is (\partial)/(\partial x)(3x^2+2xy-7y^2) ?

The answer to (\partial)/(\partial x)(3x^2+2xy-7y^2) is 6x+2y

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(\partial)/(\partial x)(3x^2+2xy-7y^2)

\frac{\partial}{\partial x} (3 x^{2} + 2 x y - 7 y^{2})

6 x + 2 y

Solution steps

\frac{\partial}{\partial x} (3 x^{2} + 2 x y - 7 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) + \frac{\partial}{\partial x} (2 x y) - \frac{\partial}{\partial x} (7 y^{2})

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (7 y^{2}) = 0

= 6 x + 2 y - 0

Simplify

= 6 x + 2 y

f (x) = 3 - 5 x^{2}

f^{^{'}} (x) = x

\frac{d}{d x} (1 + x^{4})

g (x) = x, at x = 121

ln (\frac{( 2 x + 1 )}{x ^{2} - 3})

What is (\partial)/(\partial x)(3x^2+2xy-7y^2) ?
The answer to (\partial)/(\partial x)(3x^2+2xy-7y^2) is 6x+2y