What is the derivative of f(t)=t^3-9t^2+24t ?

The derivative of f(t)=t^3-9t^2+24t is 3t^2-18t+24

What is the first derivative of f(t)=t^3-9t^2+24t ?

The first derivative of f(t)=t^3-9t^2+24t is 3t^2-18t+24

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derivative of

f (t) = t^{3} - 9 t^{2} + 24 t

3 t^{2} - 18 t + 24

Solution steps

\frac{d}{d t} (t^{3} - 9 t^{2} + 24 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{3}) - \frac{d}{d t} (9 t^{2}) + \frac{d}{d t} (24 t)

\frac{d}{d t} (t^{3}) = 3 t^{2}

\frac{d}{d t} (9 t^{2}) = 18 t

\frac{d}{d t} (24 t) = 24

= 3 t^{2} - 18 t + 24

\int \frac{x}{( x ^{3} - 1 )} d x

y^{^{''}} + 16 y = 3 sin (8 t), y (0) = 0, y^{^{'}} (0) = 0

\frac{\partial}{\partial y} (\frac{3 x - 3 y}{3 x + 3 y})

x \to 0 lim (x - \frac{1}{x - 1})

\int 100 e^{0.2 x} d x

What is the derivative of f(t)=t^3-9t^2+24t ?
The derivative of f(t)=t^3-9t^2+24t is 3t^2-18t+24
What is the first derivative of f(t)=t^3-9t^2+24t ?
The first derivative of f(t)=t^3-9t^2+24t is 3t^2-18t+24