What is the derivative of 1/(2x^2-3) ?

The derivative of 1/(2x^2-3) is -(4x)/((2x^2-3)^2)

What is the first derivative of 1/(2x^2-3) ?

The first derivative of 1/(2x^2-3) is -(4x)/((2x^2-3)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{1}{2 x ^{2} - 3})

- \frac{4 x}{( 2 x ^{2} - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x ^{2} - 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((2 x^{2} - 3)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 x ^{2} - 3 ) ^{2}} \frac{d}{d x} (2 x^{2} - 3)

= - \frac{1}{( 2 x ^{2} - 3 ) ^{2}} \frac{d}{d x} (2 x^{2} - 3)

\frac{d}{d x} (2 x^{2} - 3) = 4 x

= - \frac{1}{( 2 x ^{2} - 3 ) ^{2}} \cdot 4 x

Simplify

- \frac{1}{( 2 x ^{2} - 3 ) ^{2}} \cdot 4 x : - \frac{4 x}{( 2 x ^{2} - 3 ) ^{2}}

= - \frac{4 x}{( 2 x ^{2} - 3 ) ^{2}}

\int \frac{( e ^{x^{2}} - 1 )}{x} d x

\int_{0}^{1} \frac{1}{( x - 1 ) ^{2}} d x

\frac{1 + x}{1 - x}

\int_{0}^{3} π (2 x)^{2} d x

\int \frac{1}{( 1 - y ^{2} ) ^{\frac{1}{2}}} d y

What is the derivative of 1/(2x^2-3) ?
The derivative of 1/(2x^2-3) is -(4x)/((2x^2-3)^2)
What is the first derivative of 1/(2x^2-3) ?
The first derivative of 1/(2x^2-3) is -(4x)/((2x^2-3)^2)