What is the solution for derivative of (100x/(x+y))=0 ?

The solution for derivative of (100x/(x+y))=0 is y=(100x)/(c_{1)}-x

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derivative of (100x/(x+y))=0

\frac{d}{d x} (\frac{100 x}{x + y}) = 0

y = \frac{100 x}{c _{1}} - x

Solution steps

\frac{d}{d x} (\frac{100 x}{x + y}) = 0

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

\frac{100 x}{x + y} = \int 0 d x

\int 0 d x = c_{1}

\frac{100 x}{x + y} = c_{1}

Isolate

y : y = \frac{100 x}{c _{1}} - x

y = \frac{100 x}{c _{1}} - x

x \to 5 + lim (\frac{x}{x - 5})

\int_{3}^{5} \frac{1}{x ^{2} - 1} d x

y = x^{2}, y = - 2 x^{2} + 12

\int_{l n (1)}^{l n (2)} e^{3 x} d x

\frac{d}{d x} (\frac{6 x ^{5}}{5} - 7 x)

What is the solution for derivative of (100x/(x+y))=0 ?
The solution for derivative of (100x/(x+y))=0 is y=(100x)/(c_{1)}-x