What is the derivative of 2ln(x+2) ?

The derivative of 2ln(x+2) is 2/x

What is the first derivative of 2ln(x+2) ?

The first derivative of 2ln(x+2) is 2/x

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\frac{d}{d x} (2 ln (x) + 2)

\frac{2}{x}

Solution steps

\frac{d}{d x} (2 ln (x) + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 ln (x)) + \frac{d}{d x} (2)

\frac{d}{d x} (2 ln (x)) = \frac{2}{x}

\frac{d}{d x} (2) = 0

= \frac{2}{x} + 0

Simplify

= \frac{2}{x}

y^{^{'}} = \frac{1 + x}{x y ^{12}}

n = 1 \sum \infty \frac{3}{n n}

f (x) = x^{3}, g (x) = 4 x

\frac{d}{d x} ((2 x^{3} + x^{2} - 6 x)^{\frac{2}{3}})

x \to 2 lim (\frac{x}{x ^{2} - x - 2})

What is the derivative of 2ln(x+2) ?
The derivative of 2ln(x+2) is 2/x
What is the first derivative of 2ln(x+2) ?
The first derivative of 2ln(x+2) is 2/x