What is the derivative of 2ln(+ln(x)) ?

The derivative of 2ln(+ln(x)) is 2/(xln(x))

What is the first derivative of 2ln(+ln(x)) ?

The first derivative of 2ln(+ln(x)) is 2/(xln(x))

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derivative of

2 ln (+ ln (x))

\frac{2}{x ln ( x )}

Solution steps

\frac{d}{d x} (2 ln (ln (x)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (ln (ln (x)))

Apply the chain rule:

\frac{1}{ln ( x )} \frac{d}{d x} (ln (x))

= \frac{1}{ln ( x )} \frac{d}{d x} (ln (x))

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 2 \cdot \frac{1}{ln ( x )} \cdot \frac{1}{x}

Simplify

2 \cdot \frac{1}{ln ( x )} \cdot \frac{1}{x} : \frac{2}{x ln ( x )}

= \frac{2}{x ln ( x )}

\frac{\partial}{\partial x} (9 - 2 x + 4 y - x^{2} - 4 y^{2})

f (x) = \frac{3}{x} + x, 5, 15

\frac{d}{d θ} (cos (θ) sin (θ))

\frac{1}{2 t - 1}

\int (1 - t) (7 + t^{2}) d t

What is the derivative of 2ln(+ln(x)) ?
The derivative of 2ln(+ln(x)) is 2/(xln(x))
What is the first derivative of 2ln(+ln(x)) ?
The first derivative of 2ln(+ln(x)) is 2/(xln(x))