What is (\partial)/(\partial u)(3cos(u)) ?

The answer to (\partial)/(\partial u)(3cos(u)) is -3sin(u)

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(\partial)/(\partial u)(3cos(u))

\frac{\partial}{\partial u} (3 cos (u))

- 3 sin (u)

Solution steps

\frac{\partial}{\partial u} (3 cos (u))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{\partial}{\partial u} (cos (u))

Apply the common derivative:

\frac{\partial}{\partial u} (cos (u)) = - sin (u)

= 3 (- sin (u))

Simplify

= - 3 sin (u)

\int_{1}^{2} w^{7} e^{w^{4}} d w

y^{^{'''}} + y^{^{''}} - y^{^{'}} - y = 0

\frac{d}{d x} (\frac{36}{( 1 + 3 x ) ^{3}})

(2, 2), (19, - 17)

\int tan^{3} (3 x) d x

What is (\partial)/(\partial u)(3cos(u)) ?
The answer to (\partial)/(\partial u)(3cos(u)) is -3sin(u)