What is the derivative of 2x^3-3 ?

The derivative of 2x^3-3 is 6x^2

What is the first derivative of 2x^3-3 ?

The first derivative of 2x^3-3 is 6x^2

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\frac{d}{d x} (2 x^{3} - 3)

6 x^{2}

Solution steps

\frac{d}{d x} (2 x^{3} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (3)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3) = 0

= 6 x^{2} - 0

Simplify

= 6 x^{2}

y^{^{'}} = \frac{y}{x}, y (1) = 2

\frac{d}{d x} (\frac{2 x ^{2} - 2 x + 2}{( 2 x - 1 ) ^{2}})

(4.5) (9.25)

x \to - \infty lim (\frac{5}{x})

\int (14 x + 2) d x