What is the derivative of 3x^2+x ?

The derivative of 3x^2+x is 6x+1

What is the first derivative of 3x^2+x ?

The first derivative of 3x^2+x is 6x+1

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\frac{d}{d x} (3 x^{2} + x)

6 x + 1

Solution steps

\frac{d}{d x} (3 x^{2} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d x}{d x}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d x}{d x} = 1

= 6 x + 1

\frac{\partial}{\partial x} (- 6 + 5 - 3 y)

\int e^{x} \cdot x d x

\frac{216}{x ^{2} + 36}

\int r a^{r} d r

\int (x + 1)^{5} d x