(4x(-9)^')^'

Solution

(4 x (- 9)^{^{'}})^{^{'}}

0

Solution steps

(4 x (- 9)^{'})^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 (x (- 9)^{^{'}})^{^{'}}

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = (- 9)^{'}

= 4 (x^{^{'}} (- 9)^{^{'}} + (- 9)^{^{''}} x)

x^{'} = 1

(- 9)^{'} = 0

(- 9)^{''} = 0

= 4 (1 \cdot 0 + 0 \cdot x)

Simplify

= 0

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