What is the first derivative of 7-4x ?

The first derivative of 7-4x is -4

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derivative of 7-4x

\frac{d}{d x} (7 - 4 x)

- 4

Solution steps

\frac{d}{d x} (7 - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7) - \frac{d}{d x} (4 x)

\frac{d}{d x} (7) = 0

\frac{d}{d x} (4 x) = 4

= 0 - 4

Simplify

= - 4

\int 2 x^{- 4} d x

sin (x^{2} + 1)

\frac{d}{d x} (\frac{x}{( x - 3 ) ^{2}})

y^{^{''}} + 9 y^{^{'}} + 18 y = 0

y^{^{''}} - 4 y^{^{'}} + 5 y = e^{2 x}