What is the derivative of (4b/a xsqrt(a^2-x^2)) ?

The derivative of (4b/a xsqrt(a^2-x^2)) is (4b(-2x^2+a^2))/(asqrt(a^2-x^2))

What is the first derivative of (4b/a xsqrt(a^2-x^2)) ?

The first derivative of (4b/a xsqrt(a^2-x^2)) is (4b(-2x^2+a^2))/(asqrt(a^2-x^2))

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\frac{d}{d x} (\frac{4 b}{a} x a^{2} - x^{2})

\frac{4 b ( - 2 x ^{2} + a ^{2} )}{a a ^{2} - x ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 b}{a} x a^{2} - x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{4 b}{a} \frac{d}{d x} (x a^{2} - x^{2})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = a^{2} - x^{2}

= \frac{4 b}{a} (\frac{d x}{d x} a^{2} - x^{2} + \frac{d}{d x} (a^{2} - x^{2}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (a^{2} - x^{2}) = - \frac{x}{a ^{2} - x ^{2}}

= \frac{4 b}{a} (1 \cdot a^{2} - x^{2} + (- \frac{x}{a ^{2} - x ^{2}}) x)

Simplify

\frac{4 b}{a} (1 \cdot a^{2} - x^{2} + (- \frac{x}{a ^{2} - x ^{2}}) x) : \frac{4 b ( - 2 x ^{2} + a ^{2} )}{a a ^{2} - x ^{2}}

= \frac{4 b ( - 2 x ^{2} + a ^{2} )}{a a ^{2} - x ^{2}}

\frac{x ^{\frac{3}{2}}}{3}

(\frac{t ^{3}}{t ^{8} + 5})^{2}

y = x (x - 2)

1 - 4 x + f (x)

y = (arctan (x))^{2}

What is the derivative of (4b/a xsqrt(a^2-x^2)) ?
The derivative of (4b/a xsqrt(a^2-x^2)) is (4b(-2x^2+a^2))/(asqrt(a^2-x^2))
What is the first derivative of (4b/a xsqrt(a^2-x^2)) ?
The first derivative of (4b/a xsqrt(a^2-x^2)) is (4b(-2x^2+a^2))/(asqrt(a^2-x^2))