What is the derivative of f(x)=(2x^2-4)^4 ?

The derivative of f(x)=(2x^2-4)^4 is 16x(2x^2-4)^3

What is the first derivative of f(x)=(2x^2-4)^4 ?

The first derivative of f(x)=(2x^2-4)^4 is 16x(2x^2-4)^3

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derivative of

f (x) = (2 x^{2} - 4)^{4}

16 x (2 x^{2} - 4)^{3}

Solution steps

\frac{d}{d x} ((2 x^{2} - 4)^{4})

Apply the chain rule:

4 (2 x^{2} - 4)^{3} \frac{d}{d x} (2 x^{2} - 4)

= 4 (2 x^{2} - 4)^{3} \frac{d}{d x} (2 x^{2} - 4)

\frac{d}{d x} (2 x^{2} - 4) = 4 x

= 4 (2 x^{2} - 4)^{3} \cdot 4 x

Simplify

= 16 x (2 x^{2} - 4)^{3}

\int \frac{1}{x ^{2} + 2} d (x^{2} + 1) d x

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\int e^{3 t} t d t

\int (8 x + 2)^{\frac{1}{3}} d x

What is the derivative of f(x)=(2x^2-4)^4 ?
The derivative of f(x)=(2x^2-4)^4 is 16x(2x^2-4)^3
What is the first derivative of f(x)=(2x^2-4)^4 ?
The first derivative of f(x)=(2x^2-4)^4 is 16x(2x^2-4)^3