What is the tangent of f(x)=7x-2x^2,(-1,-9) ?

The tangent of f(x)=7x-2x^2,(-1,-9) is y=11x+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=7x-2x^2,(-1,-9)

tangent of

f (x) = 7 x - 2 x^{2}, (- 1, - 9)

y = 11 x + 2

Solution steps

Find the slope of

f (x) = 7 x - 2 x^{2} : \frac{df ( x )}{d x} = 7 - 4 x

Compute the slope of

f (x) = 7 x - 2 x^{2}

(- 1, - 9) : m = 11

Find the line with slope m=

11

and passing through

(- 1, - 9) : y = 11 x + 2

y = 11 x + 2

\int (2 x + 7)^{2} d x

\int \frac{1}{1 - sin ( 2 x )} d x

(1 - 2 t)^{- 4} (t^{2} - t)^{2}

\frac{\partial}{\partial y} (2 x^{\frac{y}{z}})

\int \frac{( 1 - x ) ^{2}}{x ^{2}} d x

What is the tangent of f(x)=7x-2x^2,(-1,-9) ?
The tangent of f(x)=7x-2x^2,(-1,-9) is y=11x+2