integral from 0 to 4 of |x^2-9|

الحلّ

\int_{0}^{4} x^{2} - 9 d x

\frac{64}{3}

العشري

21.33333 \dots

خطوات الحلّ

\int_{0}^{4} x^{2} - 9 d x

إلغِ القيم المطلقة

= \int_{0}^{3} - x^{2} + 9 d x + \int_{3}^{4} x^{2} - 9 d x

\int_{0}^{3} - x^{2} + 9 d x = 18

\int_{3}^{4} x^{2} - 9 d x = \frac{10}{3}

= 18 + \frac{10}{3}

18 + \frac{10}{3}

بسّط:

\frac{64}{3}

= \frac{64}{3}

\frac{3}{2 s + 1}

f (x) = 14 - e^{x}

f (x) = 2 x + 1

(2 x - 7)^{3}

x \to 0 lim (\frac{sec ^{2} ( 3 x )}{2})