What is the derivative of-\sqrt[4]{x} ?

The derivative of-\sqrt[4]{x} is -1/(4x^{3/4)}

What is the first derivative of-\sqrt[4]{x} ?

The first derivative of-\sqrt[4]{x} is -1/(4x^{3/4)}

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- \frac{1}{4 x ^{\frac{3}{4}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply radical rule:

= - \frac{d}{d x} (x^{\frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{4} x^{\frac{1}{4} - 1}

Simplify

- \frac{1}{4} x^{\frac{1}{4} - 1} : - \frac{1}{4 x ^{\frac{3}{4}}}

= - \frac{1}{4 x ^{\frac{3}{4}}}

y = \frac{4}{1 + x ^{2}}

\frac{d ^{4} y}{d x ^{4}} + 3 y = 0

x \to 2 lim (- 1)

\int \frac{7 x}{x + 16} d x

\int_{1}^{5} \frac{x ^{2} + 4}{6 x - x ^{2}} d x

What is the derivative of-\sqrt[4]{x} ?
The derivative of-\sqrt[4]{x} is -1/(4x^{3/4)}
What is the first derivative of-\sqrt[4]{x} ?
The first derivative of-\sqrt[4]{x} is -1/(4x^{3/4)}