What is the sum from n=1 to infinity of cos(1/(n^2)) ?

The sum from n=1 to infinity of cos(1/(n^2)) is diverges

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sum from n=1 to infinity of cos(1/(n^2))

n = 1 \sum \infty cos (\frac{1}{n ^{2}})

diverges

Solution steps

n = 1 \sum \infty cos (\frac{1}{n ^{2}})

Apply Series Divergence Test:

diverges

= diverges

\frac{d}{d t} (g (t))

n = 0 \sum \infty (\frac{8}{9})^{n}

x \to 0 lim (\frac{tan ( x )}{4 x})

\int \frac{2 x}{x} d x

x \to 0 lim (+ (e^{x}))

What is the sum from n=1 to infinity of cos(1/(n^2)) ?
The sum from n=1 to infinity of cos(1/(n^2)) is diverges