What is the limit as x approaches 1+of ln(x^5-1) ?

The limit as x approaches 1+of ln(x^5-1) is -infinity

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limit as x approaches 1+of ln(x^5-1)

x \to 1 + lim (ln (x^{5} - 1))

- \infty

Solution steps

x \to 1 + lim (ln (x^{5} - 1))

Apply the Limit Chain Rule:

- \infty

= - \infty

\frac{d}{d x} ((2 x + 3) (x - 2))

arccos (\frac{x}{2})

y^{^{'}} = \frac{2 x + sec ^{2} ( x )}{2 y}, y (0) = - 3

\frac{\partial}{\partial y} (sin (x y^{2} z^{3}))

\frac{\partial}{\partial x} (6 y^{2} + 284 x - 12)

What is the limit as x approaches 1+of ln(x^5-1) ?
The limit as x approaches 1+of ln(x^5-1) is -infinity