What is the integral of (3x^2+2x)e^{(x^3+x^2)} ?

The integral of (3x^2+2x)e^{(x^3+x^2)} is e^{x^3+x^2}+C

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integral of (3x^2+2x)e^{(x^3+x^2)}

\int (3 x^{2} + 2 x) e^{(x^{3} + x^{2})} d x

e^{x^{3} + x^{2}} + C

Solution steps

\int (3 x^{2} + 2 x) e^{x^{3} + x^{2}} d x

Apply u-substitution

: \int e^{u} d u

= \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= e^{u}

Substitute back

u = x^{3} + x^{2}

= e^{x^{3} + x^{2}}

Add a constant to the solution

= e^{x^{3} + x^{2}} + C

f (x) = - x^{3} - 4 x - 3, at x = - 1

\frac{1}{( s - 2 ) ( s - 2 )}

(x^{2} + x) e^{x}

x \to 1 + lim (\frac{1}{1 - x})

8 x^{2} y^{^{'}} = y^{^{'}} + 6 x e^{- y}

What is the integral of (3x^2+2x)e^{(x^3+x^2)} ?
The integral of (3x^2+2x)e^{(x^3+x^2)} is e^{x^3+x^2}+C