What is the derivative of 1/(4y) ?

The derivative of 1/(4y) is -1/(4y^2)

What is the first derivative of 1/(4y) ?

The first derivative of 1/(4y) is -1/(4y^2)

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derivative of

\frac{1}{4 y}

- \frac{1}{4 y ^{2}}

Solution steps

\frac{d}{d y} (\frac{1}{4 y})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{d}{d y} (\frac{1}{y})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{4} \frac{d}{d y} (y^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{4} (- 1 \cdot y^{- 1 - 1})

Simplify

\frac{1}{4} (- 1 \cdot y^{- 1 - 1}) : - \frac{1}{4 y ^{2}}

= - \frac{1}{4 y ^{2}}

2 y d x + x d y = 0

\int \frac{( x ^{2} + 1 )}{x + 1} d x

\int_{0}^{5} \frac{1}{25 + x ^{2}} d x

\int \frac{c}{x ^{2}} d x

f (x) = 7 x^{15}

What is the derivative of 1/(4y) ?
The derivative of 1/(4y) is -1/(4y^2)
What is the first derivative of 1/(4y) ?
The first derivative of 1/(4y) is -1/(4y^2)