What is the derivative of y=tan^2(9x) ?

The derivative of y=tan^2(9x) is 18sec^2(9x)tan(9x)

What is the first derivative of y=tan^2(9x) ?

The first derivative of y=tan^2(9x) is 18sec^2(9x)tan(9x)

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derivative of

y = tan^{2} (9 x)

18 sec^{2} (9 x) tan (9 x)

Solution steps

\frac{d}{d x} (tan^{2} (9 x))

Apply the chain rule:

2 tan (9 x) \frac{d}{d x} (tan (9 x))

= 2 tan (9 x) \frac{d}{d x} (tan (9 x))

\frac{d}{d x} (tan (9 x)) = sec^{2} (9 x) \cdot 9

= 2 tan (9 x) sec^{2} (9 x) \cdot 9

Simplify

= 18 sec^{2} (9 x) tan (9 x)

x \frac{d y}{d x} + y = x

\int (x e^{3 x}) d x

\int \frac{1}{x ln ( 4 x )} d x

y = (\frac{4 x ^{2} - 5}{2 - x})^{3}

y^{^{'}} - \frac{2}{x} y = \frac{y ^{3}}{x ^{2}}, y (1) = 1

What is the derivative of y=tan^2(9x) ?
The derivative of y=tan^2(9x) is 18sec^2(9x)tan(9x)
What is the first derivative of y=tan^2(9x) ?
The first derivative of y=tan^2(9x) is 18sec^2(9x)tan(9x)