What is the integral from 1 to 5 of 6/x ?

The integral from 1 to 5 of 6/x is 6ln(5)

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integral from 1 to 5 of 6/x

\int_{1}^{5} \frac{6}{x} d x

6 ln (5)

Solution steps

\int_{1}^{5} \frac{6}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{1}^{5} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= 6 [ln ∣ x ∣]_{1}^{5}

Compute the boundaries:

ln (5)

= 6 ln (5)

\int 6 x + 8 d x

\frac{d}{d x} (\frac{( e ^{x} - e ^{- x} )}{2})

\frac{d}{d x} (\frac{x}{( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}})

\int \frac{2 x ^{2}}{( x ^{2} - 1 ) ^{2}} d x

x \to - \infty lim (x - (x))

What is the integral from 1 to 5 of 6/x ?
The integral from 1 to 5 of 6/x is 6ln(5)