What is the derivative of y=2x^3+4x^2-x+2 ?

The derivative of y=2x^3+4x^2-x+2 is 6x^2+8x-1

What is the first derivative of y=2x^3+4x^2-x+2 ?

The first derivative of y=2x^3+4x^2-x+2 is 6x^2+8x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = 2 x^{3} + 4 x^{2} - x + 2

6 x^{2} + 8 x - 1

Solution steps

\frac{d}{d x} (2 x^{3} + 4 x^{2} - x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (4 x^{2}) - \frac{d x}{d x} + \frac{d}{d x} (2)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 6 x^{2} + 8 x - 1 + 0

Simplify

= 6 x^{2} + 8 x - 1

\int 3 x^{- 1} d x

2 x y d x + (x^{2} - 1) d y = 0

\int_{0}^{\infty} 3 y e^{- 3 y} d y

\int (sec^{4} (x)) d x

f (x) = \frac{cos ( x )}{1 + sin ( x )}

What is the derivative of y=2x^3+4x^2-x+2 ?
The derivative of y=2x^3+4x^2-x+2 is 6x^2+8x-1
What is the first derivative of y=2x^3+4x^2-x+2 ?
The first derivative of y=2x^3+4x^2-x+2 is 6x^2+8x-1