What is the derivative of (2x+5(3x-4)) ?

The derivative of (2x+5(3x-4)) is 12x+7

What is the first derivative of (2x+5(3x-4)) ?

The first derivative of (2x+5(3x-4)) is 12x+7

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\frac{d}{d x} ((2 x + 5) (3 x - 4))

12 x + 7

Solution steps

\frac{d}{d x} ((2 x + 5) (3 x - 4))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 2 x + 5, g = 3 x - 4

= \frac{d}{d x} (2 x + 5) (3 x - 4) + \frac{d}{d x} (3 x - 4) (2 x + 5)

\frac{d}{d x} (2 x + 5) = 2

\frac{d}{d x} (3 x - 4) = 3

= 2 (3 x - 4) + 3 (2 x + 5)

Simplify

2 (3 x - 4) + 3 (2 x + 5) : 12 x + 7

= 12 x + 7

sin (2 x + 2)

\int co tan (\frac{x}{3}) d x

y^{^{''}} + 9 y = 2 cos (3 t)

x \to 0 lim (- \frac{2}{x})

\frac{d}{d x} (\frac{x}{x ^{2} + y ^{2} + z ^{2}})

What is the derivative of (2x+5(3x-4)) ?
The derivative of (2x+5(3x-4)) is 12x+7
What is the first derivative of (2x+5(3x-4)) ?
The first derivative of (2x+5(3x-4)) is 12x+7