What is (\partial)/(\partial x)(cos(x^2y^3)) ?

The answer to (\partial)/(\partial x)(cos(x^2y^3)) is -sin(x^2y^3)*2y^3x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(cos(x^2y^3))

\frac{\partial}{\partial x} (cos (x^{2} y^{3}))

- sin (x^{2} y^{3}) \cdot 2 y^{3} x

Solution steps

\frac{\partial}{\partial x} (cos (x^{2} y^{3}))

Treat

y

as a constant

Apply the chain rule:

- sin (x^{2} y^{3}) \frac{\partial}{\partial x} (x^{2} y^{3})

= - sin (x^{2} y^{3}) \frac{\partial}{\partial x} (x^{2} y^{3})

\frac{\partial}{\partial x} (x^{2} y^{3}) = 2 y^{3} x

= - sin (x^{2} y^{3}) \cdot 2 y^{3} x

\int \frac{x + 1}{x ^{3} - 6 x ^{2} + 9 x} d x

x \to 0 lim (- (\frac{6 x}{x ^{4}}))

\int (4 x + 1) d x

\int x e^{- \frac{x}{10}} d x

\int_{0}^{2} 2 e^{x} d x

What is (\partial)/(\partial x)(cos(x^2y^3)) ?
The answer to (\partial)/(\partial x)(cos(x^2y^3)) is -sin(x^2y^3)*2y^3x