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Popular >

area f(x)=x^2,x=0,x=2

Solution

area

f (x) = x^{2}, x = 0, x = 2

Solution

\frac{8}{3}

+1

Decimal Notation

2.66666 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} ∣ x ∣^{2} d x

Solve

\int_{0}^{2} ∣ x ∣^{2} d x : \frac{8}{3}

The area is:

= \frac{8}{3}

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\frac{6 e ^{s} s - 5 e ^{s}}{( 6 s + 1 ) ^{2}}

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\int \frac{x ^{3} + 22}{x ^{2} + 7 x + 12} d x

tangent of y=3e^x+x,(0,3)tangent of

y = 3 e^{x} + x, (0, 3)

derivative of 2x^2-8

\frac{d}{d x} (2 x^{2} - 8)

derivative of 7/((7-x^8)^{3/2)}derivative of

\frac{7}{( 7 - x ^{8} ) ^{\frac{3}{2}}}

Frequently Asked Questions (FAQ)

What is area f(x)=x^2,x=0,x=2 ?
The answer to area f(x)=x^2,x=0,x=2 is 8/3