What is (\partial)/(\partial x)(4cos(3x)) ?

The answer to (\partial)/(\partial x)(4cos(3x)) is -12sin(3x)

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(\partial)/(\partial x)(4cos(3x))

\frac{\partial}{\partial x} (4 cos (3 x))

- 12 sin (3 x)

Solution steps

\frac{\partial}{\partial x} (4 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{\partial}{\partial x} (3 x)

= - sin (3 x) \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 x) = 3

= 4 (- sin (3 x) \cdot 3)

Simplify

= - 12 sin (3 x)

\int 2 x (4 x - 3)^{3} d x

\frac{2}{( 3 x ^{2} + 7 ) ^{2}}

\int \frac{1}{( x - 1 ) ( x + 3 )} d x

\int (sin (x))^{3} d x

What is (\partial)/(\partial x)(4cos(3x)) ?
The answer to (\partial)/(\partial x)(4cos(3x)) is -12sin(3x)