What is the d/(dt)(2e^t+2e^{2t}) ?

The d/(dt)(2e^t+2e^{2t}) is 2e^t+4e^{2t}

What is the first d/(dt)(2e^t+2e^{2t}) ?

The first d/(dt)(2e^t+2e^{2t}) is 2e^t+4e^{2t}

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\frac{d}{d t} (2 e^{t} + 2 e^{2 t})

2 e^{t} + 4 e^{2 t}

Solution steps

\frac{d}{d t} (2 e^{t} + 2 e^{2 t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2 e^{t}) + \frac{d}{d t} (2 e^{2 t})

\frac{d}{d t} (2 e^{t}) = 2 e^{t}

\frac{d}{d t} (2 e^{2 t}) = 4 e^{2 t}

= 2 e^{t} + 4 e^{2 t}

\int \frac{2 x + 5}{9 - x ^{2}} d x

y = sin (e^{2 x})

\frac{d}{d x} (\frac{x + 3}{8 x ^{2} e ^{x}})

x \to 0 + lim (2^{x})

\int \frac{e ^{x}}{e ^{2 x} + e ^{x} + 2} d x

What is the d/(dt)(2e^t+2e^{2t}) ?
The d/(dt)(2e^t+2e^{2t}) is 2e^t+4e^{2t}
What is the first d/(dt)(2e^t+2e^{2t}) ?
The first d/(dt)(2e^t+2e^{2t}) is 2e^t+4e^{2t}