What is the integral of 1/(sqrt(x+2)) ?

The integral of 1/(sqrt(x+2)) is 2sqrt(x+2)+C

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integral of 1/(sqrt(x+2))

\int \frac{1}{x + 2} d x

2 x + 2 + C

Solution steps

\int \frac{1}{x + 2} d x

Apply u-substitution

: \int 2 d u

= \int 2 d u

Integral of a constant:

\int a d x = a x

= 2 u

Substitute back

u = x + 2

= 2 x + 2

Add a constant to the solution

= 2 x + 2 + C

x \to - 3 lim (- x + 6 - 3)

(3 x^{2} + 1)^{2}

\frac{d}{d x} (- 4 sin (x) - 9 ln (x) + 11)

\frac{d ^{5}}{d x ^{5}} (\frac{1}{x - 1})

What is the integral of 1/(sqrt(x+2)) ?
The integral of 1/(sqrt(x+2)) is 2sqrt(x+2)+C