What is the derivative of 2t-sin(2t) ?

The derivative of 2t-sin(2t) is 2-cos(2t)*2

What is the first derivative of 2t-sin(2t) ?

The first derivative of 2t-sin(2t) is 2-cos(2t)*2

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derivative of

2 t - sin (2 t)

2 - cos (2 t) \cdot 2

Solution steps

\frac{d}{d t} (2 t - sin (2 t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2 t) - \frac{d}{d t} (sin (2 t))

\frac{d}{d t} (2 t) = 2

\frac{d}{d t} (sin (2 t)) = cos (2 t) \cdot 2

= 2 - cos (2 t) \cdot 2

\int cos^{3} (x) d x

\int (x^{3} + 3 x) e^{- 6 x} d x

\frac{\partial}{\partial y} (x e^{x^{2} - y^{2}})

\int (4 x + 3)^{9} d x

y = 1 n (1 n (x^{3}))

What is the derivative of 2t-sin(2t) ?
The derivative of 2t-sin(2t) is 2-cos(2t)*2
What is the first derivative of 2t-sin(2t) ?
The first derivative of 2t-sin(2t) is 2-cos(2t)*2