What is the solution for 9(t+1)(dy)/(dt)-8y=8t ?

The solution for 9(t+1)(dy)/(dt)-8y=8t is y=8t+9+c_{1}(t+1)^{8/9}

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9(t+1)(dy)/(dt)-8y=8t

9 (t + 1) \frac{d y}{d t} - 8 y = 8 t

y = 8 t + 9 + c_{1} (t + 1)^{\frac{8}{9}}

Solution steps

9 (t + 1) \frac{d y}{d t} - 8 y = 8 t

Solve linear ODE:

y = 8 t + 9 + c_{1} (t + 1)^{\frac{8}{9}}

y = 8 t + 9 + c_{1} (t + 1)^{\frac{8}{9}}

y = \frac{1}{x} + cos (2 x)

x \to 4 + lim (16 - x^{2})

\int_{0}^{1} 6 e^{2 x} d x

\frac{d}{d x} ((x^{4} + 3 x)^{- 1})

What is the solution for 9(t+1)(dy)/(dt)-8y=8t ?
The solution for 9(t+1)(dy)/(dt)-8y=8t is y=8t+9+c_{1}(t+1)^{8/9}