What is the limit as x approaches+0-of arctan(1/x) ?

The limit as x approaches+0-of arctan(1/x) is -pi/2

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limit as x approaches+0-of arctan(1/x)

x \to + 0 - lim (arctan (\frac{1}{x}))

- \frac{π}{2}

Solution steps

x \to 0 - lim (arctan (\frac{1}{x}))

Apply the Limit Chain Rule:

- \frac{π}{2}

= - \frac{π}{2}

\frac{- a}{x ^{2}} + \frac{a}{( x - 2 ) ^{2}}

f (x) = \frac{2 x + 3}{x ^{2} + 3 x + 15}

\int_{0}^{2} \frac{1}{4 - 2 x} d x

\int_{1}^{5} (2 + 3 x - x^{2}) d x

\frac{1}{10 x}

What is the limit as x approaches+0-of arctan(1/x) ?
The limit as x approaches+0-of arctan(1/x) is -pi/2