What is (\partial)/(\partial x)(L-x*cos(b)) ?

The answer to (\partial)/(\partial x)(L-x*cos(b)) is -cos(b)

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(\partial)/(\partial x)(L-x*cos(b))

\frac{\partial}{\partial x} (L - x \cdot cos (b))

- cos (b)

Solution steps

\frac{\partial}{\partial x} (L - x cos (b))

Treat

L, b

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (L) - \frac{\partial}{\partial x} (x cos (b))

\frac{\partial}{\partial x} (L) = 0

\frac{\partial}{\partial x} (x cos (b)) = cos (b)

= 0 - cos (b)

Simplify

= - cos (b)

y^{^{''}} + 4 y^{^{'}} + 3 y = e^{- x}, y (0) = 0, y^{^{'}} (1) = 2

\int y cos (y) d y

(- \frac{1}{2}, 7), (1, - 1)

e^{- y} cos (x) + \frac{d y}{d x} sin^{2} (x) = 0

\frac{d}{d x} (x^{4} (x + 2)^{3})

What is (\partial)/(\partial x)(L-x*cos(b)) ?
The answer to (\partial)/(\partial x)(L-x*cos(b)) is -cos(b)