What is the limit as x approaches 1+of arctan(ln(x-1)) ?

The limit as x approaches 1+of arctan(ln(x-1)) is -pi/2

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limit as x approaches 1+of arctan(ln(x-1))

x \to 1 + lim (arctan (ln (x - 1)))

- \frac{π}{2}

Decimal Notation

- 1.57079 \dots

Solution steps

x \to 1 + lim (arctan (ln (x - 1)))

Apply the Limit Chain Rule:

- \frac{π}{2}

= - \frac{π}{2}

n = 1 \sum \infty \frac{12}{- 5 ^{n}}

w e^{7 w}

f (x) = x^{- 15}

y^{^{'}} + \frac{1}{200 + 3 t} y = 12

\int \frac{1}{9 v ^{2} - 16} d v

What is the limit as x approaches 1+of arctan(ln(x-1)) ?
The limit as x approaches 1+of arctan(ln(x-1)) is -pi/2