What is the integral from-infinity to 0 of 1/(7-6x) ?

The integral from-infinity to 0 of 1/(7-6x) is diverges

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integral from-infinity to 0 of 1/(7-6x)

\int_{- \infty}^{0} \frac{1}{7 - 6 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{7 - 6 x} d x

Compute the indefinite integral:

\int \frac{1}{7 - 6 x} d x = - \frac{1}{6} ln ∣ 7 - 6 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{7 - 6 x} d x =

diverges

= diverges

arctan (2 y)

\int 3 x^{3} e^{2 x} d x

\frac{\partial}{\partial x} (arctan (x - 2 y))

\int x - x d x

\frac{2}{x}

What is the integral from-infinity to 0 of 1/(7-6x) ?
The integral from-infinity to 0 of 1/(7-6x) is diverges