What is the derivative of 1/((x+1)) ?

The derivative of 1/((x+1)) is -1/((x+1)^2)

What is the first derivative of 1/((x+1)) ?

The first derivative of 1/((x+1)) is -1/((x+1)^2)

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\frac{d}{d x} (\frac{1}{( x + 1 )})

- \frac{1}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{( x + 1 )})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

= - \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= - \frac{1}{( x + 1 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x + 1 ) ^{2}}

\frac{d}{d x} (arccsc (- x^{2}))

\int (5 x^{2}) d x

\int \frac{tan ^{2} ( x )}{2 sec ( x )} d x

\int_{0}^{π} 4 x cos (x) d x

\frac{d}{d x} (\frac{1}{in ( x - 1 )})

What is the derivative of 1/((x+1)) ?
The derivative of 1/((x+1)) is -1/((x+1)^2)
What is the first derivative of 1/((x+1)) ?
The first derivative of 1/((x+1)) is -1/((x+1)^2)