What is the derivative of x^2-4x+3 ?

The derivative of x^2-4x+3 is 2x-4

What is the first derivative of x^2-4x+3 ?

The first derivative of x^2-4x+3 is 2x-4

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\frac{d}{d x} (x^{2} - 4 x + 3)

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3) = 0

= 2 x - 4 + 0

Simplify

= 2 x - 4

f (x) = \frac{( e ^{x} )}{x ^{2} + 1}

x \to 3 lim (\frac{5 x}{6 - 2 x})

\int \frac{( x ^{2} )}{9 - x ^{2}} d x

\frac{\partial}{\partial x} (3 y cos (x))

x \to 0 lim (\frac{1}{x ^{3}})

What is the derivative of x^2-4x+3 ?
The derivative of x^2-4x+3 is 2x-4
What is the first derivative of x^2-4x+3 ?
The first derivative of x^2-4x+3 is 2x-4