What is the derivative of sqrt(a^2-x^2)+aarcsin(x/a) ?

The derivative of sqrt(a^2-x^2)+aarcsin(x/a) is (-x+a)/(sqrt(a^2-x^2))

What is the first derivative of sqrt(a^2-x^2)+aarcsin(x/a) ?

The first derivative of sqrt(a^2-x^2)+aarcsin(x/a) is (-x+a)/(sqrt(a^2-x^2))

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Popular >

\frac{d}{d x} (a^{2} - x^{2} + a arcsin (\frac{x}{a}))

\frac{- x + a}{a ^{2} - x ^{2}}

Solution steps

\frac{d}{d x} (a^{2} - x^{2} + a arcsin (\frac{x}{a}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a^{2} - x^{2}) + \frac{d}{d x} (a arcsin (\frac{x}{a}))

\frac{d}{d x} (a^{2} - x^{2}) = - \frac{x}{a ^{2} - x ^{2}}

\frac{d}{d x} (a arcsin (\frac{x}{a})) = \frac{a}{a ^{2} - x ^{2}}

= - \frac{x}{a ^{2} - x ^{2}} + \frac{a}{a ^{2} - x ^{2}}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- x + a}{a ^{2} - x ^{2}}

\int x - \frac{1}{2} x d x

\frac{\partial}{\partial y} (tan (2 + 2 x^{2} y^{4} z^{2}))

\frac{d}{d x} (\frac{x ^{2}}{10})

\int \frac{5}{x + 1} d x

\frac{d y}{d x} = 2 y^{2}

What is the derivative of sqrt(a^2-x^2)+aarcsin(x/a) ?
The derivative of sqrt(a^2-x^2)+aarcsin(x/a) is (-x+a)/(sqrt(a^2-x^2))
What is the first derivative of sqrt(a^2-x^2)+aarcsin(x/a) ?
The first derivative of sqrt(a^2-x^2)+aarcsin(x/a) is (-x+a)/(sqrt(a^2-x^2))