What is the solution for y^{''}=3tcos(9t) ?

The solution for y^{''}=3tcos(9t) is y= 1/243 (-9tcos(9t)+2sin(9t))+c_{1}t+c_{2}

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y^{''}=3tcos(9t)

y^{^{''}} = 3 t cos (9 t)

y = \frac{1}{243} (- 9 t cos (9 t) + 2 sin (9 t)) + c_{1} t + c_{2}

Solution steps

y^{''} (t) = 3 t cos (9 t)

Solve

y^{''} (t) = 3 t cos (9 t) : y^{'} (t) = \frac{1}{27} (9 t sin (9 t) + cos (9 t)) + c_{1}

Solve

y^{'} (t) = \frac{1}{27} (9 t sin (9 t) + cos (9 t)) + c_{1} : y = \frac{1}{243} (- 9 t cos (9 t) + 2 sin (9 t)) + c_{1} t + c_{2}

y = \frac{1}{243} (- 9 t cos (9 t) + 2 sin (9 t)) + c_{1} t + c_{2}

\frac{\partial}{\partial x} (- 3 x \cdot x y)

f (x) = 1 + 2 x

\frac{\partial}{\partial y} (\frac{x + y}{x y})

y^{^{''}} - 5 y^{^{'}} - 6 y = 0

\int 51 - 14 x - x^{2} d x

What is the solution for y^{''}=3tcos(9t) ?
The solution for y^{''}=3tcos(9t) is y= 1/243 (-9tcos(9t)+2sin(9t))+c_{1}t+c_{2}