What is the solution for ((y^'-e-t+4))/y =-4 ?

The solution for ((y^'-e-t+4))/y =-4 is y= t/4+e/4-17/16+(c_{1})/(e^{4t)}

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((y^'-e-t+4))/y =-4

\frac{( y ^{^{'}} - e - t + 4 )}{y} = - 4

y = \frac{t}{4} + \frac{e}{4} - \frac{17}{16} + \frac{c _{1}}{e ^{4 t}}

Solution steps

\frac{( y ^{'} ( t ) - e - t + 4 )}{y} = - 4

Solve linear ODE:

y = \frac{t}{4} + \frac{e}{4} - \frac{17}{16} + \frac{c _{1}}{e ^{4 t}}

y = \frac{t}{4} + \frac{e}{4} - \frac{17}{16} + \frac{c _{1}}{e ^{4 t}}

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\frac{d}{d x} (3 x^{- 1} + 5 π)

What is the solution for ((y^'-e-t+4))/y =-4 ?
The solution for ((y^'-e-t+4))/y =-4 is y= t/4+e/4-17/16+(c_{1})/(e^{4t)}