What is area 7cos(9x),7-7cos(9x),0, pi/9 ?

The answer to area 7cos(9x),7-7cos(9x),0, pi/9 is (7sqrt(3)pi+126)/(27sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area 7cos(9x),7-7cos(9x),0, pi/9

area

7 cos (9 x), 7 - 7 cos (9 x), 0, \frac{π}{9}

\frac{7 3 π + 126}{27 3}

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{9}} ∣ 7 cos (9 x) - (7 - 7 cos (9 x)) ∣ d x

Solve

\int_{0}^{\frac{π}{9}} ∣ 7 cos (9 x) - (7 - 7 cos (9 x)) ∣ d x : \frac{7 3 π + 126}{27 3}

The area is:

= \frac{7 3 π + 126}{27 3}

x y^{^{'}} + 2 y = x^{2}

\int_{0}^{1} \frac{9}{x ( 1 + x )} d x

\frac{d y}{d x} = \frac{x}{y}, y (0) = - 5

\frac{d}{d x} (ln (\frac{1}{2 x}))

ln (3^{x})

What is area 7cos(9x),7-7cos(9x),0, pi/9 ?
The answer to area 7cos(9x),7-7cos(9x),0, pi/9 is (7sqrt(3)pi+126)/(27sqrt(3))