What is the integral from 0 to infinity of e^{-x/2} ?

The integral from 0 to infinity of e^{-x/2} is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to infinity of e^{-x/2}

\int_{0}^{\infty} e^{- \frac{x}{2}} d x

2

Solution steps

\int_{0}^{\infty} e^{- \frac{x}{2}} d x

Compute the indefinite integral:

\int e^{- \frac{x}{2}} d x = - 2 e^{- \frac{x}{2}} + C

Compute the boundaries:

\int_{0}^{\infty} e^{- \frac{x}{2}} d x = 0 - (- 2)

= 0 - (- 2)

Simplify

= 2

\int_{0}^{3} (3 x - x^{2}) d x

3 e^{- 2 t} cos (3 t)

x \to 3 lim (\frac{1}{3 - x})

y^{^{'}} = \frac{4 x ^{4} e ^{\frac{y}{x}} + x ^{2} y ^{2}}{x ^{3} y}

\int x^{3} x^{2} - 81 d x

What is the integral from 0 to infinity of e^{-x/2} ?
The integral from 0 to infinity of e^{-x/2} is 2