What is the integral from 0 to 3 of (2^x) ?

The integral from 0 to 3 of (2^x) is 7/(ln(2))

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integral from 0 to 3 of (2^x)

\int_{0}^{3} (2^{x}) d x

\frac{7}{ln ( 2 )}

Decimal Notation

10.09886 \dots

Solution steps

\int_{0}^{3} 2^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{2 ^{x}}{ln ( 2 )}]_{0}^{3}

Compute the boundaries:

\frac{7}{ln ( 2 )}

= \frac{7}{ln ( 2 )}

y^{^{''}} + 2 y^{^{'}} + 4 y = 50 cos (x)

\int 2 e^{2 x} sin (e^{2 x}) d x

x y^{^{'}} + y = - 6 x y^{2}

\frac{3}{2} x^{\frac{2}{3}}

\frac{\partial}{\partial y} (a ln (x^{2} + y^{2}))

What is the integral from 0 to 3 of (2^x) ?
The integral from 0 to 3 of (2^x) is 7/(ln(2))