What is the limit as x approaches 0 of (3x+1)/(7x) ?

The limit as x approaches 0 of (3x+1)/(7x) is diverges

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limit as x approaches 0 of (3x+1)/(7x)

x \to 0 lim (\frac{3 x + 1}{7 x})

diverges

Solution steps

x \to 0 lim (\frac{3 x + 1}{7 x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{3 x + 1}{7 x}) = \infty

x \to 0 - lim (\frac{3 x + 1}{7 x}) = - \infty

= diverges

x^{3}, at x = 2

\int (x - 1)^{2} \cdot x^{3} \cdot (2 - x) d x

\frac{d y}{d x} = \frac{5 x}{9 y}

\frac{d}{d x} (7 e^{e})

\frac{\partial}{\partial x} ((x^{3} + y^{2})^{\frac{1}{2}})

What is the limit as x approaches 0 of (3x+1)/(7x) ?
The limit as x approaches 0 of (3x+1)/(7x) is diverges