What is (\partial)/(\partial x)(4u(x,y)) ?

The answer to (\partial)/(\partial x)(4u(x,y)) is 4u(,y*1)

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(\partial)/(\partial x)(4u(x,y))

\frac{\partial}{\partial x} (4 u (x, y))

4 u (, y \cdot 1)

Solution steps

\frac{\partial}{\partial x} (4 u (x, y))

Treat

u, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 u \frac{\partial}{\partial x} (x, y)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 u (, y \frac{\partial}{\partial x} (x))

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 4 u (, y \cdot 1)

\frac{1}{3 x ^{2}}

\frac{\partial}{\partial x} (x^{2} (1 + 2 y))

\frac{d}{d x} (\frac{1}{2} x^{2} 36 - x^{2})

n = 0 \sum \infty 2^{n} 1^{n}

\int \frac{1}{( x ^{2} + 1 ) ^{2}} d x

What is (\partial)/(\partial x)(4u(x,y)) ?
The answer to (\partial)/(\partial x)(4u(x,y)) is 4u(,y*1)